Moles of electrons:
The moles of electrons that are transferred are 12F
A balanced equation:
2 moles of Aluminium metal react with excess copper(II) nitrate.
[tex]2Al + 3Cu{(NO_3)}_2 \rightarrow 2Al{(NO_3)}_3 +3 Cu[/tex]
Given:
Moles of Aluminium = 2
As Aluminium goes from 0 to +3 oxidation state
[tex]Al \rightarrow Al^{3+} + 3e^-[/tex]
And copper goes from +2 to 0
[tex]Cu^{2+} + 2e^-\rightarrow Cu[/tex]
On balancing the number of electrons we get:
For 1 mole of Al [tex]6e^-[/tex] is required.
Therefore for 2 moles of Al,
Total [tex](2\times6)[/tex]F mole of electrons
Where F= Faraday's constant= 96500 C
So, 12F moles of electrons are transferred.
Learn more about Faraday's Law here,
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