The molarity of an HCl solution if 41.73 mL of HCl reacts with 7.8111 grams of sodium carbonate is 1.77M. Details about molarity can be found below.
The molarity of a solution can be calculated by dividing the number of moles of the substance by its volume.
According to this question, 7.8111 grams of sodium carbonate (106 g/mol) is given. The number of moles of sodium carbonate is calculated as follows:
no of moles = 7.811g ÷ 106g/mol = 0.074mol
Molarity of HCl = 0.074mol ÷ 0.04173L
Molarity of HCl = 1.77M
Therefore, the molarity of an HCl solution if 41.73 mL of HCl reacts with 7.8111 grams of sodium carbonate is 1.77M.
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