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HURRY
A –0.06 C charge is placed is in a uniform electric field with a strength of 200 N/C. What is the magnitude and direction of the force on the charge?

12 N in the opposite direction of the field
12 N in the same direction of the field
3333 N up in the opposite direction of the field
3333 N in the same direction of the field

Respuesta :

smlyons31phasdus

Answer:

12

N

in the direction opposite to electric field.

Explanation:

Force on a charged particle

q

due to electric field

E

is given by

→

F

=

q

→

E

|

F

|

=

−

0.06

C

×

200

N

C

=

−

12 N

Here negative indicates that force is in the direction opposite to electric field.

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