The domain of the graph of the that represents the side length of the mirror is 2 ≤ x ≤3
The given parameters are:
The area (y) of a square of side length x is:
y = x²
Make x the subject
x = √y
When y = 9, we have:
x = √9 = 3
When y = 4, we have:
x = √4 = 2
This means that the domain of the graph of the that represents the side length of the mirror is 2 ≤ x ≤3
See attachment for the graph
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