Respuesta :
1)The strength of the magnetic field for particle 1 will be 2.8 T.
2)The magnitude of the magnetic force exerted on the particle will be 0.12 N.
What is a magnetic field?
It is the type of field where the magnetic force is obtained. With the help of a magnetic field. The magnetic force is obtained it is the field felt around a moving electric charge.
The given data in the problem is;
q₁ has a charge = 2.7 μc
v₁ is the velocity of particle 1 = 1 773 m/s.
F is magnetic force = 5.75 × 10–3 n,
q₂ has a charge of 42.0 μc
v₂ is the velocity of 1.21 × 103 m/s.
[tex]\rm F_{B2}[/tex] is the magnitude of the magnetic force exerted on particle 2=?
The megnetic force for case 1 is found as;
[tex]\rm F_{B1}= qvB SIN \alpha_1 \\\\ 5.75 \times 10^{-3} =2.7 \times 10^{-6}\times 773 \times B sin 90^0 \\\\ B=\frac{5.75 \times 10^{-3}}{2.7 \times 10^{-6} \timesd 773 \times sin 90^0} \\\\ B=2.8 \ T[/tex]
The megnetic force for case 2 is found as;
[tex]\rm F_{B2} = q_2v_2bsin \alpha_2 \\\\ 42\times 10^{-6} \times 1.21 \times 10^3 \times 2.8 \times sin 55^0 \\\\ F_{B2}=0.12 T[/tex]
Hence the value of the megnetic force exerted on particle 2 will be 0.00122 T.
To learn more about the magnetic field refer to the link;
https://brainly.com/question/19542022
Answer:
last one and second one
Explanation:
Particle q1 has a charge of 2.7 μC and a velocity of 773 m/s. If it experiences a magnetic force of 5.75 × 10–3 N, what is the strength of the magnetic field?
2.8
T
In the same magnetic field, particle q2 has a charge of 42.0 μC and a velocity of 1.21 × 103 m/s. What is the magnitude of the magnetic force exerted on particle 2?
0.12
N
