If 0.380 mol of barium nitrate is allowed to react with an excess of phosphoric acid, 0.127 moles of barium phosphate could be formed.
The number of moles of a compound can be calculated stoichiometrically as follows:
Based on this question, the following chemical equation is given:
Ba (NO3)2+ H3PO4 → Ba3(PO4)2+ HNO3
The balanced equation is as follows:
3Ba(NO3)2 + 2H3PO4 → Ba3(PO4)2 + 6HNO3
3 moles of barium nitrate produces 1 mole of barium phosphate
Therefore, 0.380 moles of barium nitrate will produce 0.380/3 = 0.127moles of barium phosphate.
Learn more about stoichiometry at: https://brainly.com/question/9743981