The work done by the applied force on the metal bar in the xy-plane is 34.52 J.
The work done by the applied force is determined from the product of the force and the displacement of the object.
The magnitude of the force is calculated as follows;
|F| = √(Fy² + Fx²)
|F| = √(6.88² + 2.62²)
|F| = 7.36 N
The resultant displacement of the object is calculated as follows;
|s| = √(y² + x²)
|s| = √(3.7² + 2.88²)
|s| = 4.69 m
W = F.s
W = 7.36 x 4.69
W = 34.52 J
The complete question is below:
Find the work done by the applied force.
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