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f(x) = 32x
g(x) = 4x + 1
Find
(1) (a). Include any restrictions on the domain.
322
40+1)
O
O
4x+1
=
х
O A. (1) (a) =
(1) () = x
B. (1) (a) = 482, « 0
c. (1) (a) = fie & F-4
O D. () (a) = 442, a > 0
32x
4.x+1

fx 32x gx 4x 1 Find 1 a Include any restrictions on the domain 322 401 O O 4x1 х O A 1 a 1 x B 1 a 482 0 c 1 a fie amp F4 O D a 442 a gt 0 32x 4x1 class=

Respuesta :

Hrishii

Answer:

Option A is the correct answer

Step-by-step explanation:

[tex]f(x)=\sqrt[3]{2x}[/tex]

[tex]g(x)=4x+1[/tex]

[tex]\bigg(\frac{f}{g}\bigg)(x)=\frac{\sqrt[3]{2x}}{4x+1},\:x\neq -\frac{1}{4}[/tex]

Because by plugging x = -1/4 denominator of the fraction would become zero.

Division by zero is not defined.

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