Hello.
First, let the number be r.
5 times r is written like this:
[tex]\rm{5r}[/tex]
Now, add 45:
[tex]\mathrm{5r+45}[/tex]
Now, the sum of 5r+45 is equal to the sum of 85 and 140:
[tex]\mathrm{5r+45=85+140}[/tex]
In order to solve this equation, we need to add 85 and 140:
[tex]\mathrm{5r+45=225}[/tex]
Now, subtract 45 from both sides:
[tex]\mathrm{5r+45-45=225-45}[/tex]
[tex]\mathrm{5r=225-45}[/tex]
[tex]\mathrm{5r=180}[/tex]
The last step is to divide both sides by 5:
[tex]\mathrm{r=36}[/tex]
Therefore, the answer is
[tex]\rm{r=36}[/tex]
I hope it helps.
Have a nice day.
[tex]\boxed{imperturbability}[/tex]
