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par 1/2
In a volcanic eruption, 3.8 km of mountain
with a density of 1739 kg/m” was lifted an
average height of 403 m.
The acceleration of gravity is 9.81 m/s2.
How much energy was released in this eruption?
Answer in units of J.

part 2/2
The energy released by thermonuclear bombs is measured in megatons of TNT, where 1 megaton of sqrt(T) is 4.2 * 10 ^ 15 * J Convert this energy release into megatons of TNT. Answer in units of Mton TNT.

Respuesta :

indrawboy

part 1

mass = ρ x V

mass = 1739 kg/m³ x 3.8 km³ = 6608.2 kg

PE (potential energy)= mgh

PE = 6608.2 kg x 9.81 x 403

PE = 2.61 x 10⁷ J

part 2

megaton of TNT (Mt) =4.2 x 10¹⁵ J

convert PE to Mt:

2.61 x 10⁷ J : 4.2 x 10¹⁵ J = 6.21 x 10⁻⁹ Mt

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