Hi !
[tex]∫ \frac{t}{t + 1}dt[/tex]
We need to prove that it is equal to
[tex]∫ \frac{u - 1}{u}du[/tex]
As per given options, Substitute u by t+1
[tex] = > ∫ \frac{u - 1}{t + 1} du[/tex]
Then given t = u-1
[tex] = > ∫ \frac{t}{t + 1} du[/tex]
Then substitue the third given value also
[tex] = > ∫ \frac{t}{t + 1} dt[/tex]
Therefore, it's proved
~Hope it helps
