This problem is providing information about the moles of ammonia that are consumed in excess copper(II) oxide and the produced moles of nitrogen, copper and water are required.
Chemical equation:
At first instance, we must write the balanced chemical reaction that takes place when the aforementioned reactants are reacted, in agreement to the law of conservation of mass:
[tex]2NH_3+3CuO\rightarrow N_2+3Cu+3H_2O[/tex]
Mole ratios:
Next, since 6.5 moles of ammonia, NH3, is given, it turns out possible for us to apply the following mole ratios in order to calculate the required moles of each product:
[tex]6.5molNH_3*\frac{1molN_2}{2molNH_3} =3.25molN_2\\\\6.5molNH_3*\frac{3molCu}{2molNH_3} =9.75molCu\\\\6.5molNH_3*\frac{3molH_2O}{2molNH_3} =9.75molH_2O[/tex]
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