In ∆ABD
[tex]\\ \sf\longmapsto Area=\dfrac{1}{2}bh=\dfrac{1}{2}(7\times 4)[/tex]
In ∆BCD
[tex]\\ \sf\longmapsto Area=\dfrac{1}{2}(7\times 4)[/tex]
Now
IN PARALLELOGRAM ABCD
[tex]\\ \sf\longmapsto Area=\dfrac{1}{2}(7\times 4)+\dfrac{1}{2}(7\times 4)[/tex]
Option A
