Help with this please.
Answer:
[tex](\frac{11}{2} ,5 )[/tex] or (5.5,5)
Step-by-step explanation:
midpoint formula : [tex](\frac{x_1+x_2}{2} ,\frac{y_1+y_2}{2} )[/tex]
where (x1,y1) and (x2,y2) are the two given points.
We want to find the midpoint of A and B where A has coordinates of (8,2) and B has coordinates of (3,8)
To do so we simply plug in the x and y values of the coordinates into the formula
Note that (x1,y1) = (8,2) so x1 = 8 and y1 = 2
and
(x2,y2) = (3,8) so x2 = 3 and y2 = 8
Recall the midpoint formula
[tex](\frac{x_1+x_2}{2} ,\frac{y_1+y_2}{2} )[/tex]
We have x1 = 8, y1 = 2, x2 = 3 , y2 = 8
* plug in values into formula *
[tex](\frac{8+3}{2} ,\frac{2+8}{2} )[/tex]
add 8 and 3 , and 2 and 8
[tex](\frac{11}{2} ,\frac{10}{2} )[/tex]
reduce fractions
[tex](\frac{11}{2} ,5 )[/tex]
The midpoint would be at (11/2,5) or (5.5,5)