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in a collision, a car of mass 1000kg travelling at 24m/s comes to rest in 1.2s calculate
a. the change in momentum of the car
b. the steady stopping force applied to the car​

Respuesta :

homeworkmaker121219

Answer:

a. 24,000

b. -20,000 N

Explanation:

a. p = m•v

1,000•24 = 24,000

1,000•0 = 0

∆p = 24,000

b. F = m•a

a = ∆v/∆t

a = -24/1.2

a = -20 m/s²

F = 1,000•(-20)

F = -20,000

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