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George weeded 1/5 of the garden,and summer weeded some too,when they were finished, 2/3 of the garden still needed to be weeded.What fraction of the garden did summer weed?

Respuesta :

The answer is 2/15 because if you change 1/5 to 3/15 and 2/3 to 10/15 and then you add you get 13/15 and there is 2/15 left

Summer weeded [tex]\frac{2}{15}[/tex] of the garden

  • The fraction of the garden weeded by Gorge = 1/5
  • The fraction of the garden weeded by summer = ?
  • The fraction of the garden that is still needed to be weeded is [tex]\frac{2}{3}[/tex]
  • The whole garden = 1

Further Explanation

To determine the fraction of the garden that summer weeded = the whole garden - the fraction of the garden weeded by gorge + the fraction of the garden that is still needed to be weeded  

It can be expressed as:

1 – ([tex]\frac{1}{5}[/tex] + [tex]\frac{2}{3}[/tex]) (firstly, let solve the fractions in bracket)

= [tex]\frac{1}{5}[/tex] + [tex]\frac{2}{3}[/tex] (15 is the smallest number that can divide both denominator), therefore we have:

= (3 x 1) + (5 x 2) / 15

= 3 + 10 / 15

= [tex]\frac{13}{15}[/tex]

Thus, the fraction of the garden weeded by gorge and the garden that is still needed to be weeded is [tex]\frac{13}{15}[/tex]

Step 2:

To derive the final answer to this question, Recall the whole garden = 1, therefore, we have

= 1 – [tex]\frac{13}{15}[/tex] (can also be expressed as [tex]\frac{1}{1}[/tex] – [tex]\frac{13}{15}[/tex]) therefore we have:

= [tex]\frac{1}{1}[/tex] – [tex]\frac{13}{15}[/tex] (15 is the smallest number that divide both denominator), therefore we have:

= (15 x 1) – (1 x 13) / 15

= 15 – 13 / 15

= [tex]\frac{2}{15}[/tex].

Thus, the fraction of the garden weeded by summer is [tex]\frac{2}{15}[/tex].

You can also use this Method:

To determine the fraction of the garden that summer weeded = the whole garden – the fraction of the garden weeded by Gorge – the fraction of the garden that is still needed to be weeded.

Step 1:

= 1 – [tex]\frac{1}{5}[/tex] – [tex]\frac{2}{3}[/tex] (can also be expressed as [tex]\frac{1}{1}[/tex] - [tex]\frac{1}{5}[/tex] – [tex]\frac{2}{3}[/tex]

= ([tex]\frac{1}{1}[/tex] – [tex]\frac{1}{5}[/tex]) – [tex]\frac{2}{3}[/tex] (firstly let solve the fraction in bracket)

= [tex]\frac{1}{1}[/tex] – [tex]\frac{1}{5}[/tex] (5 is the smallest number that can divide both denominator)

= (5 x 1) – (1 x 1)

= 5 – 1  / 5

= [tex]\frac{4}{5}[/tex]

Step 2:

Now, we should subtract the fraction we derived and the fraction of the garden that is still needed to be weeded. Therefore, we have:

= [tex]\frac{4}{5}[/tex] – [tex]\frac{2}{3}[/tex] (15 is the lowest number that can divide both denominator)

Therefore, we have:

= (3 x 4) – (5 x 2)

= 12 – 10 / 15

= [tex]\frac{2}{15}[/tex]

Thus, the fraction of the garden weeded by summer is [tex]\frac{2}{15}[/tex]

The principle of BODMAS was used in solving this number problem due to the fact that the question deals with fractions. The smallest number used to divide the denominator is also known as the lowest common denominator (LCD).

LEARN MORE:

  • Numbers: brainly.com/question/2906770
  • fraction brainly.com/question/6201432
  • What does BODMAS stand for https://brainly.com/question/9352422

KEYWORDS:

  • bodmas
  • denominator
  • fraction
  • garden
  • lowest common denominator
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