Simplify: –3(y + 2)2 – 5 + 6y What is the simplified product in standard form?

standard form, I assume is ay^2+by+c
so expand this stuff
-3(y+2)^2-5+6y
do exponent first
(y+2)^2=(y+2)(y+2)=y²+2y+2y+4=y²+4y+4
now

-3(y²+4y+4)-5+6y
multiply/distribute
-3y²-12y-12-5+6y
regroup like terms
-3y²-12y+6y-12-5
-3y²-6y-17
that is standard form

Answer Link

Lanuel Lanuel · Answer 2 · 2021-11-02T19:31:53+01:00

The simplified product in standard form is [tex]-3y^2 -6y -17[/tex]

Given the following equation:

[tex]-3(y + 2)^2 - 5 + 6y[/tex]

To find the simplified product in standard form:

A quadratic equation is a mathematical expression that one of its variables is to the degree of 2 and as such, it has two roots.

In Mathematics, the standard form of a quadratic equation is given by;

[tex]ax^2 + bx + c = 0[/tex]

Simplifying the given mathematical equation, we have;

[tex]-3(y + 2)^2 - 5 + 6y\\\\-3(y + 2)(y+2) - 5 + 6y\\\\-3(y^2 + 2y +2y+4) -5 + 6y\\\\-3y^2 -6y -6y-12-5+6y\\\\-3y^2 -12y -17+6y\\\\-3y^2 -6y -17[/tex]

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