Respuesta :
x2 − 2x − 15 = 0
(x+3)(x-5) = 0
x +3 = 0 so x = -3
x - 5 = 0 so x = 5
answer is d.x = 5
(x+3)(x-5) = 0
x +3 = 0 so x = -3
x - 5 = 0 so x = 5
answer is d.x = 5
Answer:
x=5
Step-by-step explanation:
One of the solutions to [tex]x^2 - 2x - 15 = 0[/tex] is x = −3
To find out the other solution, we factor the x^2-2x-15
Product is -15 and sum is -2
[tex]-5 \cdot 3 = -15[/tex]
[tex]-5+3= -2[/tex]
So factors are -5 and 3
[tex]x^2 - 2x - 15 = 0[/tex]
[tex](x-5)(x+3)= 0[/tex]
we set each factor =0 and solve for x
[tex]x-5=0, x=5[/tex]
[tex]x+3=0, x=-3[/tex]
other solution is x=5