There are 10 different groups of friends could you take with you
Given
You just got a free ticket for a boat ride, and you can bring along 2 friends.
Unfortunately, you have 5 friends who want to come along.
The combination is a process of selection of elements from a set of elements in which the order of selection does not matter.
The combination is determined by the following formula;
[tex]\rm ^np_r = \dfrac{n!}{(n-r)! \times r!}[/tex]
Where P is the number of groups.
n is the number of people to choose from.
r is the number of people that we choose.
Therefore,
The number of ways groups of friends could you take with you is;
[tex]\rm ^np_r = \dfrac{n!}{(n-r)! \times r!}\\\\\rm ^5p_2 = \dfrac{5!}{(5-2)! \times 2!}\\\\\rm ^5p_2 = \dfrac{5!}{3! \times 2!}\\\\\rm ^5p_2 = \dfrac{5 \times 4 \times 3\times 2\times 1}{2\times 1 \times 3\times 2\times 1}}\\\\ ^5p_2 = \dfrac{20}{2}\\\\ ^5p_2 = 10[/tex]
Hence, there are 10 different groups of friends could you take with you.
To know more about Combination click the link given below.
https://brainly.com/question/15562556
