What is the point-slope equation of the line through the point (−5, 5) that is perpendicular to the line whose equation is 5x = 3y?
A. y − 5 = 5/3(x + 5)
B. y − 5 = −3/5(x + 5)
C. y − 5 = 3/5(x + 5)
D. y − 5 = −5/3(x + 5)

the equation of the line that passes through (x1,y1) and has a slope of m is
y-y1=m(x-x1)

the slopes of perpendiculare lines multiply to -1

y=mx+b
m=slope
5x=3y
3y=5x
y=5/3x
slope is 5/3
5/3 times what=-1
what=-3/5

slope is -3/5
point is (-5,5)
y-5=-3/5(x-(-5))
y-5=-3/5(x+5)

B is answer

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What is the point-slope equation of the line through the point (−5, 5) that is perpendicular to the line whose equation is 5x = 3y? A. y − 5 = 5/3(x + 5) B. y − 5 = −3/5(x + 5) C. y − 5 = 3/5(x + 5) D. y − 5 = −5/3(x + 5)

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What is the point-slope equation of the line through the point (−5, 5) that is perpendicular to the line whose equation is 5x = 3y?
A. y − 5 = 5/3(x + 5)
B. y − 5 = −3/5(x + 5)
C. y − 5 = 3/5(x + 5)
D. y − 5 = −5/3(x + 5)