macipope
contestada

Please help me !!!

( the directions are at the top of the picture )

Answer what you can correctly for a brainliest and also get a thanks ! Don't answer if you don't know it .

Please help me the directions are at the top of the picture Answer what you can correctly for a brainliest and also get a thanks Dont answer if you dont know it class=

Respuesta :

This is a quadratic equation, x^2-5x-14 = 0, you solve this through x_1 = 5/2 + sqrt[(5/2)^2+14] and x_2 = 5/2 - sqrt[(5/2)^2+14] which gives us the solutions x = 7 and x = -2, so the dimensions of the rectangle is (x+2) and (x-7)
arthurpdc
[tex]27)~S=x^2-5x-14=(x+2)(x-7)\to\text{The two expressions are:}\\\\(x+2)~\text{and}~(x-7).\\\\ 28)~(x^2-14x+48)\div(x-6)=\dfrac{(x-6)(x-8)}{(x-6)}=x-8\\\\ 29)~(x^2-9)\div(x-3)=\dfrac{(x-3)(x+3)}{(x-3)}=x+3\\\\ 30)~\dfrac{x^2y+x^2z-5y-5z}{y+z}=\dfrac{x^2(y+z)-5(y+z)}{(y+z)}=\\\\=\dfrac{(x^2-5)(y+z)}{(y+z)}=x^2-5[/tex]

Otras preguntas

Q&A Education