Answer:
[tex]\boxed {\boxed {\sf 4.5 \ m/s \ in \ the \ positive \ direction}}[/tex]
Explanation:
We are asked to find the final velocity of the boat.
We are given the initial velocity, acceleration, and time. Therefore, we will use the following kinematic equation.
[tex]v_f= v_i + at[/tex]
The initial velocity is 2.7 meters per second. The acceleration is 0.15 meters per second squared. The time is 12 seconds.
- [tex]v_i[/tex]= 2.7 m/s
- a= 0.15 m/s²
- t= 12 s
Substitute the values into the formula.
[tex]v_f = 2.7 \ m/s + (0.15 \ m/s^2)(12 \ s)[/tex]
Multiply the numbers in parentheses.
[tex]v_f= 2.7 \ m/s + (0.15 \ m/s/s * 12 \ s)[/tex]
[tex]v_f = 2.7 \ m/s + (0.15 \ m/s *12)[/tex]
[tex]\v_f=2.7 \ m/s + (1.8 \ m/s)[/tex][tex]v_f=2.7 \ m/s + (1.8 \ m/s)[/tex]
Add.
[tex]v_f=4.5 \ m/s[/tex]
The final velocity of the boat is 4.5 meters per second in the positive direction.
