Answer:
3.78 gm O2
Explanation:
In the reaction represented by the equation 2Al2O3 → 4A1 + 302, calculate the theoretical amount in grams of oxygen, O2 produced if 11.84 grams Al2O3 decomposes?
for every 2 moles of Al2O3, 3 mole of 02 are produced
molecular weight of Al2O3 =(2X27) + (3X32) =54+96= 150
11.84 gm Al2O3 = 11.84/150 moles =0.0789 moles
This will produce 3/2 X 0.0789 moles of O2 = 0.118 moles O2
mol wt of O2 is 32
0.118 moles weighs 0.118X32 = 3.78 gm O2
