Explanation:
Correct option is
A
As LHS=RHS, formula is dimensionally correct.
Writing the dimensions of either side of the given equation.
LHS=8=displacement=[M
0
LT
0
]
RHS=ut=velocity×time=[M
0
LT
−1
][T]=[M
0
LT
0
]
and
2
1
at
2
=(acceleration)×(time)
2
=[M
0
LT
−2
][T]
2
=[M
0
LT
0
]
As LHS=RHS, formula is dimensionally correct.
