Answer: 2r² - 5r + 4
Step-by-step explanation:
Since expression = 3A + 2B [subsitute in values of A&B]
⇒ = 3(r – 2) + 2(r² – 4r + 5) [expnad the brackets]
= 3r - 6 + 2r² - 8r + 10 [group like terms ins stan. form]
= 2r² - 8r + 3r + 10 - 6 [simplify like terms]
= 2r² - 5r + 4
Note:
Standard form is ax² + bx + c (where x is any variable, in this case 'r', and a,b,c are the coefficients)
