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Question : If an object is thrown straight up into the air with a velocity 112 feet/second, then it’s height h(t) above the ground t seconds later is given by the formula h(t)=-16t^2 + 112t

Find the height after 1 and after 2 seconds. [find h(1) and h(2).]

h(1)=
h(2)=

HELP will give Brainly 24 pts Question If an object is thrown straight up into the air with a velocity 112 feetsecond then its height ht above the ground t seco class=
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