The voltage drop be when running this heater is 13.508 Volts.
Given the following data:
To determine the voltage drop be when running this heater:
First of all, we would calculate the amount of current that is flowing through this heater.
Mathematically, current is given by this formula in accordance with Ohm's law:
[tex]I=\frac{P}{V}[/tex]
Where:
Substituting the given parameters into the formula, we have;
[tex]I=\frac{1265}{115}[/tex]
Current, I = 11 Amperes.
Note: The resistance of a 14-gage copper wire at 1000 feet is 3.07 Ohms.
For the voltage drop:
Mathematically, the voltage drop is given by this formula in accordance with Ohm's law:
[tex]V=IR\\\\V=2 \times length \times I \times \frac{R}{1000} \\ \\V=2 \times 200 \times 11 \times \frac{3.07}{1000}\\\\V=4400 \times 0.00307[/tex]
Voltage drop = 13.508 Volts.
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