The slope-intercept form of the equation of the line that passes through (8, 4) and (0, 2) is: [tex]y = \frac{1}{4}x + 2[/tex]
Recall:
- You can expressed the equation of a line in slope-intercept form as y = mx + b.
- slope = m
- y-intercept = b
- Equation in point-slope form can be rewritten and expressed as y = mx + b
Given, [tex]y - 4 = \frac{1}{4}(x -8)[/tex]
Rewrite in the form of y = mx + b
[tex]y - 4 = \frac{1}{4}x - 2[/tex]
[tex]y - 4 + 4 = \frac{1}{4}x - 2 + 4\\\\y = \frac{1}{4}x + 2[/tex]
Therefore, the slope-intercept form of the equation of the line that passes through (8, 4) and (0, 2) is: [tex]y = \frac{1}{4}x + 2[/tex]
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