The mass percent of nitrogen in C₁₄H₁₉NO₂ is 6%
- We'll begin by calculating the molar mass of C₁₄H₁₉NO₂ . This can be obtained as follow:
Molar mass of C₁₄H₁₉NO₂ = (12×14) + (1×19) + 14 + (16×2)
= 233 g/mol
- Next, we shall determine the mass of N in C₁₄H₁₉NO₂. This can be obtained as follow:
Mass of N in C₁₄H₁₉NO₂ = 14 g/mol
- Finally, we shall determine the mass percent of nitrogen, N, in C₁₄H₁₉NO₂. This can be obtained as follow:
Molar mass of C₁₄H₁₉NO₂ = 233 g/mol
Mass of N in C₁₄H₁₉NO₂ = 14 g /mol
Percentage of N =?
[tex]Percent = \frac{mass of element}{mass of compound} * 100\\\\= \frac{14}{233} * 100[/tex]
= 6%
Therefore, the mass percent of nitrogen in C₁₄H₁₉NO₂ is 6%
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