The balanced chemical equation for the reaction is
6Cs(s) + 2CsNO₂(s) —> 4Cs₂O(s) + N₂(g)
From the question given above, we were told that:
solid cesium reacts with solid cesium nitrite to form solid cesium oxide and nitrogen gas.
The equation for the reaction can be written as follow:
Caesium => Cs
Caesium nitrite => CsNO₂
cesium oxide => Cs₂O
nitrogen gas => N₂
Caesium + Caesium nitrite —> Caesium oxide + Nitrogen gas
Cs + CsNO₂ —> Cs₂O + N₂
The above equation can be balance as follow:
Cs + CsNO₂ —> Cs₂O + N₂
There are 2 atoms of N on the right side and 1 atom on the left side. It can be balance by writing 2 before CsNO₂ as shown below:
Cs + 2CsNO₂ —> Cs₂O + N₂
There are 2 atoms of Cs on the right side and a total 3 atoms on the left side. It can be balance by writing 6 before Cs and 4 before Cs₂O as shown below:
6Cs(s) + 2CsNO₂(s) —> 4Cs₂O(s) + N₂(g)
Now the equation is balanced
Learn more: https://brainly.com/question/11502387
