Answer:
Step-by-step explanation:
CD is Pole
∠CAD = 4° {Alternate interior angles}
ΔCAD,
[tex]\dfrac{opposite \ side}{adjacent \ side}= tan 4\\\\ \dfrac{90}{AD}=tan \ 4\\\\ \dfrac{90}{AD} = 0.069\\\\90 = 0.069*AD\\\\ \dfrac{90}{0.069}=AD\\\\AD = 1304 \ ft[/tex]
In ΔCDB,
∠B = 5° {Alternate interior angles}
[tex]Tan \ 5 = \dfrac{90}{BD}\\\\0.09* BD = 90\\\\BD = \dfrac{90}{0.09}\\\\BD = 1000 \ ft[/tex]
