Answer:
1800 N
Explanation:
We know that ,
[tex]\longrightarrow\sf Force = k \dfrac{q_1 q_2}{r^2}\\ [/tex]
[tex]\longrightarrow\sf Force = \dfrac{ 9 * 10^9 * 5 * 10^2 * 1 * 10^2 * 10 ^{-12}}{ ( 0.5)^2}\\[/tex]
[tex]\longrightarrow\sf Force = \dfrac{ 9 * 10^9 * 5 * 10^2 * 1 * 10^2 * 10 ^{-12}}{ 25 * 10^{-2}}[/tex]
[tex]\longrightarrow\sf Force = 1800 \ N \\\\[/tex]
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