Respuesta :

Answer:

see explanation

Step-by-step explanation:

If 2 angles and the included side of one triangle are congruent to 2 angles and the included side of another triangle, then the triangles are congruent.

NQ is an angle bisector then ∠ MNQ = ∠ PNQ

∠ M = ∠ N , so the triangle is isosceles with 2 equal legs, then

MN = PN

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∠ MNQ = ∠ PNQ

MN = PN ( included sides between the 2 angles )

∠ M = ∠ N

Δ MNQ ≅ Δ PNQ by the ASA postulate

devishri1977

Answer:

Step-by-step explanation:

In Δ MNP,

∠NMQ ≅ ∠NPQ

⇒ NM = NP - ------> (I)     {Sides opposite to equal angles are equal}

In ΔMNQ & ΔPNQ,

∠MNQ  ≅ ∠PNQ             {NQ is angle bisector}

NM  = NP                     {from (I)}

∠NMQ ≅ ∠NPQ           {Given}

ΔMNQ ≅ ΔPNQ          -  Angle Side Angle  {ASA congruent}

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