Respuesta :

isaree27

Answer:

Hereeeeeeeeeeeeeeeee

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prishagupta035

(1)

=(x+4)(x+5)

=x(x+5)+4(x+5)

=x^+5x+4x+20

=x^+9x+20

(2)

=(x+4)(x-5)

=x(x-5)+4(x-5)

=x^-5x+4x-20

=x^-x-20

(3)

=(x-4)(x+5)

=x(x+5)-4(x+5)

=x^+5x-4x+20

=x^+x+20

(4)

=(x-4)(x-5)

=x(x-5)-4(x-5)

=x^5x-4x+20

=x^-x+20

(5)

=(x+7y)(x+7y)

=x(x+7y)+7y(x+7y)

=x^+7xy+7xy+49y^

=x^+14xy+49y^

It was very easy

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