Answer:
answer is
[tex] \frac{6 {y}^{2} + 1}{2y} [/tex]
Step-by-step explanation:
since nothing is written under 3y, is denominator is 1.
in the other fraction denominator is 2y.
hence the 2 fractions are
[tex] \frac{3y}{1} \: and \: \frac{1}{2y} [/tex]
to write as a single fraction denominator should be common which will be the product of 1 and 2y which is 2y.
and the numerator should be cross multiplied. thus numerator is
[tex](3y \times 2y) + (1 \times 1) \\ = 6 {y}^{2} + 1[/tex]
