manismith
manismith
05-06-2021
Mathematics
contestada
What is the solution for the equation?
Respuesta :
angstar4
angstar4
05-06-2021
Cross multiply
5(b3-2) = 2(3b2 - 2b2 -5)
5b3 - 10 = 6b3 - 4b2 - 10
5b3 = 6b3 - 4b2
0 = b3 - 4b2
0 = b2(b - 4)
b2 = 0 —> b = 0
b-4=0 —> b = 4
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