You can't solve for the zeros by factoring because the function is not factorable.
I'll show you what happens:
f(x) = 6x^2 + 6x + 12
To solve for the zeros (when f(x)=0), set f(x) equal to 0.
0 = 6x^2 + 6x + 12
First you can factor out a 6.
0 = 6(x^2 + x + 2)
Divide by 6.
0 = x^2 + x + 2
Now you need two integers that add up to the coefficient of x (1) and multiply to the product of the last term and the coefficient of x^2. This number is 2.
No two integers add up to 1 and multiply to 2.
