2 CuCl2 + 2 NaNO3 ---> Cu(NO3)2 + 2 NaCl



If 15 grams of copper (II) chloride react with 20 grams of sodium nitrate, Which is the limiting reagent

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In the reaction between copper chloride and sodium nitrate, copper chloride will be the limiting reagent as it has less number of moles.

What are limiting reagents?

Limiting reagents are the chemical species that are present in less amount compared to another and get consumed 100 % hence limiting the product formation.

CuCl₂ + 2NaNO₃ → Cu(NO₃)₂ + 2NaCl

Moles of copper chloride: n = 15 ÷ 134.5 = 0.11 moles

Moles of sodium nitrate: n = 20 ÷ 85 = 0.23 moles

From the above reaction, it is seen that 1 mole of copper chloride requires 2 moles of sodium nitrate. So, 0.11 moles will need 0.22 moles of sodium nitrate.

From this, it can be concluded that sodium nitrate is in excess and copper chloride is within the limit.

Therefore, copper chloride will be the limiting reagent and will be consumed first.

Learn more about limiting reagents here:

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