Respuesta :
There are two equations hidden in the language here:
a + b = 56 and a - b = 10.
if you do (a+b) + (a-b) then you get:
(a+b) + (a-b) = 66 = a + b + a - b
The b's cancel, so you get 2a = 66, which means a = 33. You can use this to solve for b in one of the above equations by plugging in a = 33 and figuring out what b has to be. Then you will have your two numbers.
a + b = 56 and a - b = 10.
if you do (a+b) + (a-b) then you get:
(a+b) + (a-b) = 66 = a + b + a - b
The b's cancel, so you get 2a = 66, which means a = 33. You can use this to solve for b in one of the above equations by plugging in a = 33 and figuring out what b has to be. Then you will have your two numbers.
x + y = 56
x - y = 10 so x = y + 10
y + 10 + y = 56
2y +10 = 56
2y = 56 -10
2y = 46
y = 46/2
y = 23
x = y + 10 = 23 + 10 =33
Answer: The numbers are 23 and 33
Proof:
sum: 23 + 33 = 56
difference: 33 -23 = 10
x - y = 10 so x = y + 10
y + 10 + y = 56
2y +10 = 56
2y = 56 -10
2y = 46
y = 46/2
y = 23
x = y + 10 = 23 + 10 =33
Answer: The numbers are 23 and 33
Proof:
sum: 23 + 33 = 56
difference: 33 -23 = 10