Answer:
q = 1.95 x 10⁻⁶ C = 1.95 μC
Explanation:
The formula for the electric field produced by a point charge is given as follows:
[tex]E = \frac{kq}{r^2}\\[/tex]
where,
E = Electric Field strength = 56000 N/C
k = Colomb's Constant = 9 x 10⁹ Nm²/C²
q = magnitude of charge = ?
r = distance = 0.65 m
Therefore,
[tex]56000\ N/C = \frac{(9\ x\ 10^9\ Nm^2/C^2)q}{(0.56\ m)^2}\\\\q = \frac{(56000\ N/C)(0.56\ m)^2}{9\ x\ 10^9\ Nm^/C^2}\\\\[/tex]
q = 1.95 x 10⁻⁶ C = 1.95 μC
