Answer:
(x+1)+(x+2)+(x+3)=39
X+1+x+2+x+3=39
6+3x=39
3x=39-6
3x=33
X=33/3
X=11
Therefore, x+1 =11+1 =12
X+2 =11+2 =13
X+3 =11+3=14
Your, 3 consecutive intigers are 12,13,14
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