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If the solubility of salicylic acid is 77.8 g/L of water at 100oC and 1.4 g/L of water at 10oC, a) calculate the minimum amount (in mL) of boiling water necessary to dissolve 2.0 g of impure salicylic acid for recrystallization. b) If the solution is cooled to room temperature and then to 10oC with an ice/water bath, what is the maximum amount of solid salicylic acid isolated after vacuum filtration

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Answer:

a. 25.7mL are necessaries.

b. 1.964g of salicylic acid can be isolated.

Explanation:

a. As the solubility of salicylicic acid in boiling water is 77.8g/L, to dissolve 2.0g of salicylic acid are necessaries:

2.0g * (1L / 77.8g) = 0.0257L =

25.7mL are necessaries

b. Then, at 10°C the solution just can dissolve 1.4g/L, that is:

0.0257L * (1.4g/L) = 0.036g of salicylic acid are dissolved.

And will precipitate:

2.0g - 0.036g =

1.964g of salicylic acid can be isolated

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