Answer: 824.6 g of NaCl are produced from 500.0 g of chlorine.
Explanation:
To calculate the moles :
[tex]\text{Moles of solute}=\frac{\text{given mass}}{\text{Molar Mass}}[/tex] [tex]\text{Moles of} Cl_2=\frac{500.00g}{71g/mol}=7.04moles[/tex]
[tex]2Na+Cl_2\rightarrow 2NaCl[/tex]
According to stoichiometry :
1 mole of [tex]Cl_2[/tex] produce = 2 moles of [tex]NaCl[/tex]
Thus 7.04 moles of [tex]Cl_2[/tex] will produce=[tex]\frac{2}{1}\times 7.04=14.08moles[/tex] of [tex]NaCl[/tex]
Mass of [tex]NaCl=moles\times {\text {Molar mass}}=14.08moles\times 58.5g/mol=824.26g[/tex]
Thus 824.6 g of NaCl are produced from 500.0 g of chlorine.
