05-03-2021
Mathematics

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Given PQ = y, RS = 4y - 15, QR = 2 +6, and PS = 4a - 6, solve for the
length of RS and QR.

Given PQ y RS 4y 15 QR 2 6 and PS 4a 6 solve for the length of RS and QR class=

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06-03-2021

Answer:

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