Respuesta :

kaymarei

Answer:

is the difference of two squares, just like (a) (above); its factors are:  

(9x^3y - 0.6a)(9x^3y + 0.6a)

Explanation:
81x^6y^2 – 0.36a^2
= 9(9x^6y^2 – 0.04a^2)
= 9 (3x^3y)^2 - (0.2a)^2
= 9(3x^3y - 0.2a)(3x^3y + 0.2a)
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