Given:
A spinner marked A, B, C is spun then a 6-sided die is rolled.
To find:
The probability of getting a B and then a 6.
Solution:
We know that,
[tex]\text{Probability}=\dfrac{\text{Favorable outcomes}}{\text{Total outcomes}}[/tex]
Total possible values for a spinner are 3. So, the probability of getting B, we get
[tex]P(B)=\dfrac{1}{3}[/tex]
Total possible values for a die are 6. So, the probability of getting 6, we get
[tex]P(6)=\dfrac{1}{6}[/tex]
Now, the probability of getting a B and then a 6 is
[tex]P(B,6)=\dfrac{1}{3}\times \dfrac{1}{6}[/tex]
[tex]P(B,6)=\dfrac{1}{18}[/tex]
The required probability is [tex]\dfrac{1}{18}[/tex].
Therefore, the correct option is D.
