Answer:
See the answer below
Explanation:
Normal height - H
Short height - h
Heterozygous - Hh
A cross involving heterozygotes would be Hh x Hh
Hh x Hh
HH Hh Hh hh
Since H is dominant over h;
HH and Hh would produce normal height phenotypes.
hh will produce a short height phenotype.
Thus;
Probability of normal height phenotype resulting from the cross = 3/4 or 75%
Probability of short height phenotype resulting from the cross = 1/4 or 25%
