Answer:
0.51 cal/g.°C
Explanation:
Step 1: Given data
- Added energy in the form of heat (Q): 14 cal
- Mass of the liquid (m): 12 g
- Initial temperature: 10.4 °C
- Final temperature: 12.7 °C
Step 2: Calculate the temperature change
ΔT = 12.7 °C - 10.4 °C = 2.3 °C
Step 3: Calculate the specific heat of the liquid (c)
We will use the following expression.
c = Q / m × ΔT
c = 14 cal / 12 g × 2.3 °C = 0.51 cal/g.°C
