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05-11-2016
Mathematics

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Find the solution of square root x+2+4 =6 and determine if it is an extraneous solution

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05-11-2016

[tex]\displaystyles \\ \sqrt{ x+2} +4 = 6 \\ \\ \sqrt{ x+2} = 6 - 4\\ \\ \sqrt{ x+2} = 2\\ \\ \Big( \sqrt{ x+2}\Big)^2 = 2^2\\ \\ x+2=4 \\ \\ x = 4-2 = \boxed{2} [/tex]

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