Answer:
[tex](x+2)^2+(y-5)^2=16[/tex]
Step-by-step explanation:
We have been given that a circle has its center at (−2, 5) and a radius of 4 units. We are asked to write the equation of the circle.
We know that standard equation of circle is in form [tex](x-h)^2+(y-k)^2=r^2[/tex], where, (h,k) represents vertex of circle and r represents radius of circle.
Upon substituting coordinates of vertex [tex](-2,5)[/tex] and [tex]r=4[/tex] in above equation, we will get:
[tex](x-(-2))^2+(y-5)^2=4^2[/tex]
[tex](x+2)^2+(y-5)^2=16[/tex]
Therefore, the equation of our given circle would be [tex](x+2)^2+(y-5)^2=16[/tex].
